Suppose I’ve two recursive features
f, g : A -> B outlined by the identical equation. Can I conclude that they’re truly equal? Is there any case once they couldn’t be?
Particularly, I am working in Haskell and I’ve two recursive features satisfying the equation
g :: Repair F -> a g (Repair x) = f $ fmap g x
F is a functor,
newtype Repair F = Repair (F (Repair F)) is its fastened level and
(a, f) is one other
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