We’re given 2 algorithms A and B such that for every enter measurement, algorithm A performs half the variety of steps algorithm B performs on the identical enter measurement.
We denote the worst time complexity of every one by $g_A(n),g_B(n)$
Additionally, we all know there is a constructive operate $f(n)$ such that $g_A(n)inOmega(f(n))$
Is it doable that $g_B(n)inOmega(f(n))$? Is it vital?
It appears naive to suppose that it’s a necessity, however I am unable to determine to contradict it.
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