There are a number of solutions to this query, however they use a barely completely different model of what it means to be an odd operate. I needed to know what I did fallacious in my strategy of making an attempt to reach at an answer.
Defn: A operate $f$ is odd if $f(x) = -f(-x)$ and a operate is even if $f(x) = f(-x)$
Suppose $f$ is even and $g$ is odd:
$$(f circ g)(x) = f(g(x)) = f(g(-x)) = f(-g(-x)) = f(-1 cdot g(-x)) $$
by properties of scalars with features:
$$ = -f(g(-x)) = -(f circ g)(-x) $$
I do know that that is fallacious, and I really feel it have to be within the 4th line that I did one thing fallacious, what’s it that’s incorrect?
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