In a proper triangle, the place the biggest non-right angle alpha is calculated, in radians as:
alpha = xPI() / (2(x+1))
the place x is the issue of instances higher that angle is in comparison with the smallest angle in that triangle, with this mentioned, x >=1.
After which, the hypotenuse is calculated as follows:
x+1=n, hypotenuse = sqrt(-4*(nth root of -1)/(((nth root of -1)-1)^2)).
Let x = 1, then hypotenuse = sqrt(2). you’ve got acquired a 1,1,sqrt(2) proper triangle.
Let x = 2, then hypotenuse = sqrt(4). you’ve got acquired a 1,sqrt(3),sqrt(4) proper triangle.
and so forth…
So, my query is: Working backwards, Suppose the hypotenuse was size of PI(), then, what’s angle alpha? what’s X? Can X be written in a clear kind, in order that PI() will be rewritten as 2 legs in a proper triangle?
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